3[x+12]=5[x+4]

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Solution for 3[x+12]=5[x+4] equation:


Simplifying
3[x + 12] = 5[x + 4]

Reorder the terms:
3[12 + x] = 5[x + 4]
[12 * 3 + x * 3] = 5[x + 4]
[36 + 3x] = 5[x + 4]

Reorder the terms:
36 + 3x = 5[4 + x]
36 + 3x = [4 * 5 + x * 5]
36 + 3x = [20 + 5x]

Solving
36 + 3x = 20 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.
36 + 3x + -5x = 20 + 5x + -5x

Combine like terms: 3x + -5x = -2x
36 + -2x = 20 + 5x + -5x

Combine like terms: 5x + -5x = 0
36 + -2x = 20 + 0
36 + -2x = 20

Add '-36' to each side of the equation.
36 + -36 + -2x = 20 + -36

Combine like terms: 36 + -36 = 0
0 + -2x = 20 + -36
-2x = 20 + -36

Combine like terms: 20 + -36 = -16
-2x = -16

Divide each side by '-2'.
x = 8

Simplifying
x = 8

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